10(3-2b)=4(1-9b)+10

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Solution for 10(3-2b)=4(1-9b)+10 equation: 



10(3-2b)=4(1-9b)+10

We move all terms to the left:

10(3-2b)-(4(1-9b)+10)=0

We add all the numbers together, and all the variables

10(-2b+3)-(4(-9b+1)+10)=0

We multiply parentheses

-20b-(4(-9b+1)+10)+30=0



We calculate terms in parentheses: -(4(-9b+1)+10), so:

4(-9b+1)+10

We multiply parentheses

-36b+4+10

We add all the numbers together, and all the variables

-36b+14

Back to the equation:

-(-36b+14)



We get rid of parentheses

-20b+36b-14+30=0

We add all the numbers together, and all the variables

16b+16=0

We move all terms containing b to the left, all other terms to the right

16b=-16

b=-16/16

b=-1

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