10(3-8(2s-5))=15(40-5s)

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Solution for 10(3-8(2s-5))=15(40-5s) equation: 



103-8(2s-5)=15(40-5s)

We move all terms to the left:

103-8(2s-5)-(15(40-5s))=0

We add all the numbers together, and all the variables

-8(2s-5)-(15(-5s+40))+103=0

We multiply parentheses

-16s-(15(-5s+40))+40+103=0



We calculate terms in parentheses: -(15(-5s+40)), so:

15(-5s+40)

We multiply parentheses

-75s+600

Back to the equation:

-(-75s+600)



We add all the numbers together, and all the variables

-16s-(-75s+600)+143=0

We get rid of parentheses

-16s+75s-600+143=0

We add all the numbers together, and all the variables

59s-457=0

We move all terms containing s to the left, all other terms to the right

59s=457

s=457/59

s=7+44/59

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