10(3-8x)=-12(2x+5)

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Solution for 10(3-8x)=-12(2x+5) equation: 



10(3-8x)=-12(2x+5)

We move all terms to the left:

10(3-8x)-(-12(2x+5))=0

We add all the numbers together, and all the variables

10(-8x+3)-(-12(2x+5))=0

We multiply parentheses

-80x-(-12(2x+5))+30=0



We calculate terms in parentheses: -(-12(2x+5)), so:

-12(2x+5)

We multiply parentheses

-24x-60

Back to the equation:

-(-24x-60)



We get rid of parentheses

-80x+24x+60+30=0

We add all the numbers together, and all the variables

-56x+90=0

We move all terms containing x to the left, all other terms to the right

-56x=-90

x=-90/-56

x=1+17/28

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