10(3/10+7)=10(1/6-x)

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Solution for 10(3/10+7)=10(1/6-x) equation:



10(3/10+7)=10(1/6-x)
We move all terms to the left:
10(3/10+7)-(10(1/6-x))=0
Domain of the equation: 6-x))!=0
We move all terms containing x to the left, all other terms to the right
-x))!=-6
x!=-6/1
x!=-6
x∈R
We add all the numbers together, and all the variables
-(10(-1x+1/6))+10(3/10+7)=0
We add all the numbers together, and all the variables
-(10(-1x+1/6))+1=0
We multiply all the terms by the denominator
-(10(-1x+1+1*6))=0
We calculate terms in parentheses: -(10(-1x+1+1*6)), so:
10(-1x+1+1*6)
We add all the numbers together, and all the variables
10(-1x+7)
We multiply parentheses
-10x+70
Back to the equation:
-(-10x+70)
We get rid of parentheses
10x-70=0
We move all terms containing x to the left, all other terms to the right
10x=70
x=70/10
x=7

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