10(3b-2)=(b-3)5

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Solution for 10(3b-2)=(b-3)5 equation: 



10(3b-2)=(b-3)5

We move all terms to the left:

10(3b-2)-((b-3)5)=0

We multiply parentheses

30b-((b-3)5)-20=0



We calculate terms in parentheses: -((b-3)5), so:

(b-3)5

We multiply parentheses

5b-15

Back to the equation:

-(5b-15)



We get rid of parentheses

30b-5b+15-20=0

We add all the numbers together, and all the variables

25b-5=0

We move all terms containing b to the left, all other terms to the right

25b=5

b=5/25

b=1/5

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