10(3k+1)=2(4k+11)

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Solution for 10(3k+1)=2(4k+11) equation: 



10(3k+1)=2(4k+11)

We move all terms to the left:

10(3k+1)-(2(4k+11))=0

We multiply parentheses

30k-(2(4k+11))+10=0



We calculate terms in parentheses: -(2(4k+11)), so:

2(4k+11)

We multiply parentheses

8k+22

Back to the equation:

-(8k+22)



We get rid of parentheses

30k-8k-22+10=0

We add all the numbers together, and all the variables

22k-12=0

We move all terms containing k to the left, all other terms to the right

22k=12

k=12/22

k=6/11

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