10(3k+1)=2(9k+1)

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Solution for 10(3k+1)=2(9k+1) equation: 



10(3k+1)=2(9k+1)

We move all terms to the left:

10(3k+1)-(2(9k+1))=0

We multiply parentheses

30k-(2(9k+1))+10=0



We calculate terms in parentheses: -(2(9k+1)), so:

2(9k+1)

We multiply parentheses

18k+2

Back to the equation:

-(18k+2)



We get rid of parentheses

30k-18k-2+10=0

We add all the numbers together, and all the variables

12k+8=0

We move all terms containing k to the left, all other terms to the right

12k=-8

k=-8/12

k=-2/3

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