10(3k+1)=3(9k+11)

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Solution for 10(3k+1)=3(9k+11) equation: 



10(3k+1)=3(9k+11)

We move all terms to the left:

10(3k+1)-(3(9k+11))=0

We multiply parentheses

30k-(3(9k+11))+10=0



We calculate terms in parentheses: -(3(9k+11)), so:

3(9k+11)

We multiply parentheses

27k+33

Back to the equation:

-(27k+33)



We get rid of parentheses

30k-27k-33+10=0

We add all the numbers together, and all the variables

3k-23=0

We move all terms containing k to the left, all other terms to the right

3k=23

k=23/3

k=7+2/3

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