10(3x+2)-(x-1)=-7(x+5)

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Solution for 10(3x+2)-(x-1)=-7(x+5) equation: 



10(3x+2)-(x-1)=-7(x+5)

We move all terms to the left:

10(3x+2)-(x-1)-(-7(x+5))=0

We multiply parentheses

30x-(x-1)-(-7(x+5))+20=0

We get rid of parentheses

30x-x-(-7(x+5))+1+20=0



We calculate terms in parentheses: -(-7(x+5)), so:

-7(x+5)

We multiply parentheses

-7x-35

Back to the equation:

-(-7x-35)



We add all the numbers together, and all the variables

29x-(-7x-35)+21=0

We get rid of parentheses

29x+7x+35+21=0

We add all the numbers together, and all the variables

36x+56=0

We move all terms containing x to the left, all other terms to the right

36x=-56

x=-56/36

x=-1+5/9

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