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10(3x+54)-5(4x+2)=2(5x+20)
We move all terms to the left:
10(3x+54)-5(4x+2)-(2(5x+20))=0
We multiply parentheses
30x-20x-(2(5x+20))+540-10=0
We calculate terms in parentheses: -(2(5x+20)), so:We add all the numbers together, and all the variables
2(5x+20)
We multiply parentheses
10x+40
Back to the equation:
-(10x+40)
10x-(10x+40)+530=0
We get rid of parentheses
10x-10x-40+530=0
We add all the numbers together, and all the variables
490!=0
There is no solution for this equation
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