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10(3x+6)2x+7=x
We move all terms to the left:
10(3x+6)2x+7-(x)=0
We add all the numbers together, and all the variables
-1x+10(3x+6)2x+7=0
We multiply parentheses
60x^2-1x+120x+7=0
We add all the numbers together, and all the variables
60x^2+119x+7=0
a = 60; b = 119; c = +7;
Δ = b2-4ac
Δ = 1192-4·60·7
Δ = 12481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(119)-\sqrt{12481}}{2*60}=\frac{-119-\sqrt{12481}}{120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(119)+\sqrt{12481}}{2*60}=\frac{-119+\sqrt{12481}}{120} $
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