10(3x+i)=2(10x-5)

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Solution for 10(3x+i)=2(10x-5) equation:


Simplifying
10(3x + i) = 2(10x + -5)

Reorder the terms:
10(i + 3x) = 2(10x + -5)
(i * 10 + 3x * 10) = 2(10x + -5)
(10i + 30x) = 2(10x + -5)

Reorder the terms:
10i + 30x = 2(-5 + 10x)
10i + 30x = (-5 * 2 + 10x * 2)
10i + 30x = (-10 + 20x)

Solving
10i + 30x = -10 + 20x

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-30x' to each side of the equation.
10i + 30x + -30x = -10 + 20x + -30x

Combine like terms: 30x + -30x = 0
10i + 0 = -10 + 20x + -30x
10i = -10 + 20x + -30x

Combine like terms: 20x + -30x = -10x
10i = -10 + -10x

Divide each side by '10'.
i = -1 + -1x

Simplifying
i = -1 + -1x

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