10(3x+x)=68

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Solution for 10(3x+x)=68 equation: 



10(3x+x)=68

We move all terms to the left:

10(3x+x)-(68)=0

We add all the numbers together, and all the variables

10(+4x)-68=0

We multiply parentheses

40x-68=0

We move all terms containing x to the left, all other terms to the right

40x=68

x=68/40

x=1+7/10

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