10(3x-2)+8=5(6x-3)+3

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Solution for 10(3x-2)+8=5(6x-3)+3 equation: 



10(3x-2)+8=5(6x-3)+3

We move all terms to the left:

10(3x-2)+8-(5(6x-3)+3)=0

We multiply parentheses

30x-(5(6x-3)+3)-20+8=0



We calculate terms in parentheses: -(5(6x-3)+3), so:

5(6x-3)+3

We multiply parentheses

30x-15+3

We add all the numbers together, and all the variables

30x-12

Back to the equation:

-(30x-12)



We add all the numbers together, and all the variables

30x-(30x-12)-12=0

We get rid of parentheses

30x-30x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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