10(3x-2)=7(5x-4)

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Solution for 10(3x-2)=7(5x-4) equation: 



10(3x-2)=7(5x-4)

We move all terms to the left:

10(3x-2)-(7(5x-4))=0

We multiply parentheses

30x-(7(5x-4))-20=0



We calculate terms in parentheses: -(7(5x-4)), so:

7(5x-4)

We multiply parentheses

35x-28

Back to the equation:

-(35x-28)



We get rid of parentheses

30x-35x+28-20=0

We add all the numbers together, and all the variables

-5x+8=0

We move all terms containing x to the left, all other terms to the right

-5x=-8

x=-8/-5

x=1+3/5

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