10(3x-5)=-11(x-12)

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Solution for 10(3x-5)=-11(x-12) equation: 



10(3x-5)=-11(x-12)

We move all terms to the left:

10(3x-5)-(-11(x-12))=0

We multiply parentheses

30x-(-11(x-12))-50=0



We calculate terms in parentheses: -(-11(x-12)), so:

-11(x-12)

We multiply parentheses

-11x+132

Back to the equation:

-(-11x+132)



We get rid of parentheses

30x+11x-132-50=0

We add all the numbers together, and all the variables

41x-182=0

We move all terms containing x to the left, all other terms to the right

41x=182

x=182/41

x=4+18/41

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