10(3y+2)=2(8y-8)

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Solution for 10(3y+2)=2(8y-8) equation: 



10(3y+2)=2(8y-8)

We move all terms to the left:

10(3y+2)-(2(8y-8))=0

We multiply parentheses

30y-(2(8y-8))+20=0



We calculate terms in parentheses: -(2(8y-8)), so:

2(8y-8)

We multiply parentheses

16y-16

Back to the equation:

-(16y-16)



We get rid of parentheses

30y-16y+16+20=0

We add all the numbers together, and all the variables

14y+36=0

We move all terms containing y to the left, all other terms to the right

14y=-36

y=-36/14

y=-2+4/7

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