10(3y-2)=10

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Solution for 10(3y-2)=10 equation: 



10(3y-2)=10

We move all terms to the left:

10(3y-2)-(10)=0

We multiply parentheses

30y-20-10=0

We add all the numbers together, and all the variables

30y-30=0

We move all terms containing y to the left, all other terms to the right

30y=30

y=30/30

y=1

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