10(4-x)=3(x-4)

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Solution for 10(4-x)=3(x-4) equation: 



10(4-x)=3(x-4)

We move all terms to the left:

10(4-x)-(3(x-4))=0

We add all the numbers together, and all the variables

10(-1x+4)-(3(x-4))=0

We multiply parentheses

-10x-(3(x-4))+40=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

-10x-3x+12+40=0

We add all the numbers together, and all the variables

-13x+52=0

We move all terms containing x to the left, all other terms to the right

-13x=-52

x=-52/-13

x=+4

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