10(4a-8)=12(a+4)

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Solution for 10(4a-8)=12(a+4) equation: 



10(4a-8)=12(a+4)

We move all terms to the left:

10(4a-8)-(12(a+4))=0

We multiply parentheses

40a-(12(a+4))-80=0



We calculate terms in parentheses: -(12(a+4)), so:

12(a+4)

We multiply parentheses

12a+48

Back to the equation:

-(12a+48)



We get rid of parentheses

40a-12a-48-80=0

We add all the numbers together, and all the variables

28a-128=0

We move all terms containing a to the left, all other terms to the right

28a=128

a=128/28

a=4+4/7

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