10(4b+1)+12b=218

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Solution for 10(4b+1)+12b=218 equation: 



10(4b+1)+12b=218

We move all terms to the left:

10(4b+1)+12b-(218)=0

We add all the numbers together, and all the variables

12b+10(4b+1)-218=0

We multiply parentheses

12b+40b+10-218=0

We add all the numbers together, and all the variables

52b-208=0

We move all terms containing b to the left, all other terms to the right

52b=208

b=208/52

b=4

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