10(4g-12)=32

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Solution for 10(4g-12)=32 equation:



10(4g-12)=32
We move all terms to the left:
10(4g-12)-(32)=0
We multiply parentheses
40g-120-32=0
We add all the numbers together, and all the variables
40g-152=0
We move all terms containing g to the left, all other terms to the right
40g=152
g=152/40
g=3+4/5

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