10(4u-1)+1u=10u+(4u-1)-63

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Solution for 10(4u-1)+1u=10u+(4u-1)-63 equation: 



10(4u-1)+1u=10u+(4u-1)-63

We move all terms to the left:

10(4u-1)+1u-(10u+(4u-1)-63)=0

We add all the numbers together, and all the variables

u+10(4u-1)-(10u+(4u-1)-63)=0

We multiply parentheses

u+40u-(10u+(4u-1)-63)-10=0



We calculate terms in parentheses: -(10u+(4u-1)-63), so:

10u+(4u-1)-63

We get rid of parentheses

10u+4u-1-63

We add all the numbers together, and all the variables

14u-64

Back to the equation:

-(14u-64)



We add all the numbers together, and all the variables

41u-(14u-64)-10=0

We get rid of parentheses

41u-14u+64-10=0

We add all the numbers together, and all the variables

27u+54=0

We move all terms containing u to the left, all other terms to the right

27u=-54

u=-54/27

u=-2

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