10(4x)=3x(x-3)

Solution for 10(4x)=3x(x-3) equation:

10(4x)=3x(x-3)

We move all terms to the left:

10(4x)-(3x(x-3))=0


We calculate terms in parentheses: -(3x(x-3)), so:

3x(x-3)

We multiply parentheses

3x^2-9x

Back to the equation:

-(3x^2-9x)


We get rid of parentheses

-3x^2+104x+9x=0

We add all the numbers together, and all the variables

-3x^2+113x=0

a = -3; b = 113; c = 0;
Δ = b2-4ac
Δ = 1132-4·(-3)·0
Δ = 12769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12769}=113$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(113)-113}{2*-3}=\frac{-226}{-6}
=37+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(113)+113}{2*-3}=\frac{0}{-6}
=0
$