10(4x+12)=-8(-10-4x)+6x

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Solution for 10(4x+12)=-8(-10-4x)+6x equation: 



10(4x+12)=-8(-10-4x)+6x

We move all terms to the left:

10(4x+12)-(-8(-10-4x)+6x)=0

We add all the numbers together, and all the variables

10(4x+12)-(-8(-4x-10)+6x)=0

We multiply parentheses

40x-(-8(-4x-10)+6x)+120=0



We calculate terms in parentheses: -(-8(-4x-10)+6x), so:

-8(-4x-10)+6x

We add all the numbers together, and all the variables

6x-8(-4x-10)

We multiply parentheses

6x+32x+80

We add all the numbers together, and all the variables

38x+80

Back to the equation:

-(38x+80)



We get rid of parentheses

40x-38x-80+120=0

We add all the numbers together, and all the variables

2x+40=0

We move all terms containing x to the left, all other terms to the right

2x=-40

x=-40/2

x=-20

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