10(4x-2)=-8x+28

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Solution for 10(4x-2)=-8x+28 equation: 



10(4x-2)=-8x+28

We move all terms to the left:

10(4x-2)-(-8x+28)=0

We multiply parentheses

40x-(-8x+28)-20=0

We get rid of parentheses

40x+8x-28-20=0

We add all the numbers together, and all the variables

48x-48=0

We move all terms containing x to the left, all other terms to the right

48x=48

x=48/48

x=1

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