10(4x-20)=3(x+90)+37x-470

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Solution for 10(4x-20)=3(x+90)+37x-470 equation: 



10(4x-20)=3(x+90)+37x-470

We move all terms to the left:

10(4x-20)-(3(x+90)+37x-470)=0

We multiply parentheses

40x-(3(x+90)+37x-470)-200=0



We calculate terms in parentheses: -(3(x+90)+37x-470), so:

3(x+90)+37x-470

We add all the numbers together, and all the variables

37x+3(x+90)-470

We multiply parentheses

37x+3x+270-470

We add all the numbers together, and all the variables

40x-200

Back to the equation:

-(40x-200)



We get rid of parentheses

40x-40x+200-200=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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