10(4x-5)+8X=-6X+3(4x+2)

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Solution for 10(4x-5)+8X=-6X+3(4x+2) equation: 



10(4x-5)+8x=-6x+3(4x+2)

We move all terms to the left:

10(4x-5)+8x-(-6x+3(4x+2))=0

We add all the numbers together, and all the variables

8x+10(4x-5)-(-6x+3(4x+2))=0

We multiply parentheses

8x+40x-(-6x+3(4x+2))-50=0



We calculate terms in parentheses: -(-6x+3(4x+2)), so:

-6x+3(4x+2)

We multiply parentheses

-6x+12x+6

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

48x-(6x+6)-50=0

We get rid of parentheses

48x-6x-6-50=0

We add all the numbers together, and all the variables

42x-56=0

We move all terms containing x to the left, all other terms to the right

42x=56

x=56/42

x=1+1/3

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