10(4y-3)=-4(1-8y)-22

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Solution for 10(4y-3)=-4(1-8y)-22 equation: 



10(4y-3)=-4(1-8y)-22

We move all terms to the left:

10(4y-3)-(-4(1-8y)-22)=0

We add all the numbers together, and all the variables

10(4y-3)-(-4(-8y+1)-22)=0

We multiply parentheses

40y-(-4(-8y+1)-22)-30=0



We calculate terms in parentheses: -(-4(-8y+1)-22), so:

-4(-8y+1)-22

We multiply parentheses

32y-4-22

We add all the numbers together, and all the variables

32y-26

Back to the equation:

-(32y-26)



We get rid of parentheses

40y-32y+26-30=0

We add all the numbers together, and all the variables

8y-4=0

We move all terms containing y to the left, all other terms to the right

8y=4

y=4/8

y=1/2

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