10(4z-8)=5(10z-4)

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Solution for 10(4z-8)=5(10z-4) equation:


Simplifying
10(4z + -8) = 5(10z + -4)

Reorder the terms:
10(-8 + 4z) = 5(10z + -4)
(-8 * 10 + 4z * 10) = 5(10z + -4)
(-80 + 40z) = 5(10z + -4)

Reorder the terms:
-80 + 40z = 5(-4 + 10z)
-80 + 40z = (-4 * 5 + 10z * 5)
-80 + 40z = (-20 + 50z)

Solving
-80 + 40z = -20 + 50z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-50z' to each side of the equation.
-80 + 40z + -50z = -20 + 50z + -50z

Combine like terms: 40z + -50z = -10z
-80 + -10z = -20 + 50z + -50z

Combine like terms: 50z + -50z = 0
-80 + -10z = -20 + 0
-80 + -10z = -20

Add '80' to each side of the equation.
-80 + 80 + -10z = -20 + 80

Combine like terms: -80 + 80 = 0
0 + -10z = -20 + 80
-10z = -20 + 80

Combine like terms: -20 + 80 = 60
-10z = 60

Divide each side by '-10'.
z = -6

Simplifying
z = -6

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