10(5+3y)=15y-(5-4y)

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Solution for 10(5+3y)=15y-(5-4y) equation: 



10(5+3y)=15y-(5-4y)

We move all terms to the left:

10(5+3y)-(15y-(5-4y))=0

We add all the numbers together, and all the variables

10(3y+5)-(15y-(-4y+5))=0

We multiply parentheses

30y-(15y-(-4y+5))+50=0



We calculate terms in parentheses: -(15y-(-4y+5)), so:

15y-(-4y+5)

We get rid of parentheses

15y+4y-5

We add all the numbers together, and all the variables

19y-5

Back to the equation:

-(19y-5)



We get rid of parentheses

30y-19y+5+50=0

We add all the numbers together, and all the variables

11y+55=0

We move all terms containing y to the left, all other terms to the right

11y=-55

y=-55/11

y=-5

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