10(5+4y)=6y-(2-8y)

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Solution for 10(5+4y)=6y-(2-8y) equation: 



10(5+4y)=6y-(2-8y)

We move all terms to the left:

10(5+4y)-(6y-(2-8y))=0

We add all the numbers together, and all the variables

10(4y+5)-(6y-(-8y+2))=0

We multiply parentheses

40y-(6y-(-8y+2))+50=0



We calculate terms in parentheses: -(6y-(-8y+2)), so:

6y-(-8y+2)

We get rid of parentheses

6y+8y-2

We add all the numbers together, and all the variables

14y-2

Back to the equation:

-(14y-2)



We get rid of parentheses

40y-14y+2+50=0

We add all the numbers together, and all the variables

26y+52=0

We move all terms containing y to the left, all other terms to the right

26y=-52

y=-52/26

y=-2

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