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10(5x-4)+3(2x-1)=12x-(2-3x)
We move all terms to the left:
10(5x-4)+3(2x-1)-(12x-(2-3x))=0
We add all the numbers together, and all the variables
10(5x-4)+3(2x-1)-(12x-(-3x+2))=0
We multiply parentheses
50x+6x-(12x-(-3x+2))-40-3=0
We calculate terms in parentheses: -(12x-(-3x+2)), so:We add all the numbers together, and all the variables
12x-(-3x+2)
We get rid of parentheses
12x+3x-2
We add all the numbers together, and all the variables
15x-2
Back to the equation:
-(15x-2)
56x-(15x-2)-43=0
We get rid of parentheses
56x-15x+2-43=0
We add all the numbers together, and all the variables
41x-41=0
We move all terms containing x to the left, all other terms to the right
41x=41
x=41/41
x=1
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