10(6b+5)-12b=-2b-10(1-8b)

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Solution for 10(6b+5)-12b=-2b-10(1-8b) equation:



10(6b+5)-12b=-2b-10(1-8b)
We move all terms to the left:
10(6b+5)-12b-(-2b-10(1-8b))=0
We add all the numbers together, and all the variables
10(6b+5)-12b-(-2b-10(-8b+1))=0
We add all the numbers together, and all the variables
-12b+10(6b+5)-(-2b-10(-8b+1))=0
We multiply parentheses
-12b+60b-(-2b-10(-8b+1))+50=0
We calculate terms in parentheses: -(-2b-10(-8b+1)), so:
-2b-10(-8b+1)
We multiply parentheses
-2b+80b-10
We add all the numbers together, and all the variables
78b-10
Back to the equation:
-(78b-10)
We add all the numbers together, and all the variables
48b-(78b-10)+50=0
We get rid of parentheses
48b-78b+10+50=0
We add all the numbers together, and all the variables
-30b+60=0
We move all terms containing b to the left, all other terms to the right
-30b=-60
b=-60/-30
b=+2

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