10(7x+41)-24=70x-3+x

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Solution for 10(7x+41)-24=70x-3+x equation: 



10(7x+41)-24=70x-3+x

We move all terms to the left:

10(7x+41)-24-(70x-3+x)=0

We add all the numbers together, and all the variables

10(7x+41)-(71x-3)-24=0

We multiply parentheses

70x-(71x-3)+410-24=0

We get rid of parentheses

70x-71x+3+410-24=0

We add all the numbers together, and all the variables

-1x+389=0

We move all terms containing x to the left, all other terms to the right

-x=-389

x=-389/-1

x=+389

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