10(8+12y)+8y=-11(1-11y)

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Solution for 10(8+12y)+8y=-11(1-11y) equation: 



10(8+12y)+8y=-11(1-11y)

We move all terms to the left:

10(8+12y)+8y-(-11(1-11y))=0

We add all the numbers together, and all the variables

10(12y+8)+8y-(-11(-11y+1))=0

We add all the numbers together, and all the variables

8y+10(12y+8)-(-11(-11y+1))=0

We multiply parentheses

8y+120y-(-11(-11y+1))+80=0



We calculate terms in parentheses: -(-11(-11y+1)), so:

-11(-11y+1)

We multiply parentheses

121y-11

Back to the equation:

-(121y-11)



We add all the numbers together, and all the variables

128y-(121y-11)+80=0

We get rid of parentheses

128y-121y+11+80=0

We add all the numbers together, and all the variables

7y+91=0

We move all terms containing y to the left, all other terms to the right

7y=-91

y=-91/7

y=-13

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