10(9-x)+x+27=10(x)9-x

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Solution for 10(9-x)+x+27=10(x)9-x equation: 



10(9-x)+x+27=10(x)9-x

We move all terms to the left:

10(9-x)+x+27-(10(x)9-x)=0

We add all the numbers together, and all the variables

-(+10x^9-1x)+10(-1x+9)+x+27=0

We add all the numbers together, and all the variables

-(+10x^9-1x)+x+10(-1x+9)+27=0

We multiply parentheses

-(+10x^9-1x)+x-10x+90+27=0

We get rid of parentheses

-10x^9+1x+x-10x+90+27=0

We do not support expression: x^9

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