10(9-x)+x=12(9-x)

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Solution for 10(9-x)+x=12(9-x) equation: 



10(9-x)+x=12(9-x)

We move all terms to the left:

10(9-x)+x-(12(9-x))=0

We add all the numbers together, and all the variables

10(-1x+9)+x-(12(-1x+9))=0

We add all the numbers together, and all the variables

x+10(-1x+9)-(12(-1x+9))=0

We multiply parentheses

x-10x-(12(-1x+9))+90=0



We calculate terms in parentheses: -(12(-1x+9)), so:

12(-1x+9)

We multiply parentheses

-12x+108

Back to the equation:

-(-12x+108)



We add all the numbers together, and all the variables

-9x-(-12x+108)+90=0

We get rid of parentheses

-9x+12x-108+90=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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