10(a+1)+14a=9-(4a+1)

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Solution for 10(a+1)+14a=9-(4a+1) equation: 



10(a+1)+14a=9-(4a+1)

We move all terms to the left:

10(a+1)+14a-(9-(4a+1))=0

We add all the numbers together, and all the variables

14a+10(a+1)-(9-(4a+1))=0

We multiply parentheses

14a+10a-(9-(4a+1))+10=0



We calculate terms in parentheses: -(9-(4a+1)), so:

9-(4a+1)

determiningTheFunctionDomain
-(4a+1)+9

We get rid of parentheses

-4a-1+9

We add all the numbers together, and all the variables

-4a+8

Back to the equation:

-(-4a+8)



We add all the numbers together, and all the variables

24a-(-4a+8)+10=0

We get rid of parentheses

24a+4a-8+10=0

We add all the numbers together, and all the variables

28a+2=0

We move all terms containing a to the left, all other terms to the right

28a=-2

a=-2/28

a=-1/14

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