10(a+3)-4(a-2)=7(a

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Solution for 10(a+3)-4(a-2)=7(a equation: 



10(a+3)-4(a-2)=7(a

We move all terms to the left:

10(a+3)-4(a-2)-(7(a)=0

We multiply parentheses

10a-4a-(7a+30+8=0

We add all the numbers together, and all the variables

6a-(7a+30+8=0

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