10(a+3)-4(a-2)=7(a+5)

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Solution for 10(a+3)-4(a-2)=7(a+5) equation: 



10(a+3)-4(a-2)=7(a+5)

We move all terms to the left:

10(a+3)-4(a-2)-(7(a+5))=0

We multiply parentheses

10a-4a-(7(a+5))+30+8=0



We calculate terms in parentheses: -(7(a+5)), so:

7(a+5)

We multiply parentheses

7a+35

Back to the equation:

-(7a+35)



We add all the numbers together, and all the variables

6a-(7a+35)+38=0

We get rid of parentheses

6a-7a-35+38=0

We add all the numbers together, and all the variables

-1a+3=0

We move all terms containing a to the left, all other terms to the right

-a=-3

a=-3/-1

a=+3

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