10(a-1)=2(a+2)-2

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Solution for 10(a-1)=2(a+2)-2 equation: 



10(a-1)=2(a+2)-2

We move all terms to the left:

10(a-1)-(2(a+2)-2)=0

We multiply parentheses

10a-(2(a+2)-2)-10=0



We calculate terms in parentheses: -(2(a+2)-2), so:

2(a+2)-2

We multiply parentheses

2a+4-2

We add all the numbers together, and all the variables

2a+2

Back to the equation:

-(2a+2)



We get rid of parentheses

10a-2a-2-10=0

We add all the numbers together, and all the variables

8a-12=0

We move all terms containing a to the left, all other terms to the right

8a=12

a=12/8

a=1+1/2

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