10(a-2)-14(a-5)=12(5a+10)

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Solution for 10(a-2)-14(a-5)=12(5a+10) equation: 



10(a-2)-14(a-5)=12(5a+10)

We move all terms to the left:

10(a-2)-14(a-5)-(12(5a+10))=0

We multiply parentheses

10a-14a-(12(5a+10))-20+70=0



We calculate terms in parentheses: -(12(5a+10)), so:

12(5a+10)

We multiply parentheses

60a+120

Back to the equation:

-(60a+120)



We add all the numbers together, and all the variables

-4a-(60a+120)+50=0

We get rid of parentheses

-4a-60a-120+50=0

We add all the numbers together, and all the variables

-64a-70=0

We move all terms containing a to the left, all other terms to the right

-64a=70

a=70/-64

a=-1+3/32

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