10(a-3)=-128

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Solution for 10(a-3)=-128 equation: 



10(a-3)=-128

We move all terms to the left:

10(a-3)-(-128)=0

We add all the numbers together, and all the variables

10(a-3)+128=0

We multiply parentheses

10a-30+128=0

We add all the numbers together, and all the variables

10a+98=0

We move all terms containing a to the left, all other terms to the right

10a=-98

a=-98/10

a=-9+4/5

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