10(a-4)-6(4-a)-(a+4)=

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Solution for 10(a-4)-6(4-a)-(a+4)= equation:


10 (a-4)-6 (4-a)-(a+4)=0

We simplify the equation to the form, which is simple to understand
10(a-4)-6(4-a)-(a+4)=0

Reorder the terms in parentheses
+(+10a-40)-6*(4-a)-(a+4)=0

Remove unnecessary parentheses
+10a-40-6+*(+4-a+)-(+a+4+)=0

Reorder the terms in parentheses
+10a-40+(-24+6a)-(a+4)=0

Remove unnecessary parentheses
+10a-40-24+6a-(+a+4+)=0

Remove unnecessary parentheses
+10a-40-24+6a-1a-4=0

We move all terms containing a to the left and all other terms to the right.
+10a+6a-1a=0+40+24+4

We simplify left and right side of the equation.
+15a=+68

We divide both sides of the equation by 15 to get a.
a=4.5333333333333

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