10(b+11)-12=2(2b-8)

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Solution for 10(b+11)-12=2(2b-8) equation:



10(b+11)-12=2(2b-8)
We move all terms to the left:
10(b+11)-12-(2(2b-8))=0
We multiply parentheses
10b-(2(2b-8))+110-12=0
We calculate terms in parentheses: -(2(2b-8)), so:
2(2b-8)
We multiply parentheses
4b-16
Back to the equation:
-(4b-16)
We add all the numbers together, and all the variables
10b-(4b-16)+98=0
We get rid of parentheses
10b-4b+16+98=0
We add all the numbers together, and all the variables
6b+114=0
We move all terms containing b to the left, all other terms to the right
6b=-114
b=-114/6
b=-19

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