10(b+2)-4(2b+8)=

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Solution for 10(b+2)-4(2b+8)= equation:


Simplifying
10(b + 2) + -4(2b + 8) = 0

Reorder the terms:
10(2 + b) + -4(2b + 8) = 0
(2 * 10 + b * 10) + -4(2b + 8) = 0
(20 + 10b) + -4(2b + 8) = 0

Reorder the terms:
20 + 10b + -4(8 + 2b) = 0
20 + 10b + (8 * -4 + 2b * -4) = 0
20 + 10b + (-32 + -8b) = 0

Reorder the terms:
20 + -32 + 10b + -8b = 0

Combine like terms: 20 + -32 = -12
-12 + 10b + -8b = 0

Combine like terms: 10b + -8b = 2b
-12 + 2b = 0

Solving
-12 + 2b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 2b = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 2b = 0 + 12
2b = 0 + 12

Combine like terms: 0 + 12 = 12
2b = 12

Divide each side by '2'.
b = 6

Simplifying
b = 6

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