10(b+2)-5(b+3)=0

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Solution for 10(b+2)-5(b+3)=0 equation:


Simplifying
10(b + 2) + -5(b + 3) = 0

Reorder the terms:
10(2 + b) + -5(b + 3) = 0
(2 * 10 + b * 10) + -5(b + 3) = 0
(20 + 10b) + -5(b + 3) = 0

Reorder the terms:
20 + 10b + -5(3 + b) = 0
20 + 10b + (3 * -5 + b * -5) = 0
20 + 10b + (-15 + -5b) = 0

Reorder the terms:
20 + -15 + 10b + -5b = 0

Combine like terms: 20 + -15 = 5
5 + 10b + -5b = 0

Combine like terms: 10b + -5b = 5b
5 + 5b = 0

Solving
5 + 5b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 5b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 5b = 0 + -5
5b = 0 + -5

Combine like terms: 0 + -5 = -5
5b = -5

Divide each side by '5'.
b = -1

Simplifying
b = -1

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