10(b+28)+30(b+2)+40=20(b+7)+10(b+7)+10

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Solution for 10(b+28)+30(b+2)+40=20(b+7)+10(b+7)+10 equation:


10(b+28)+30(b+2)+40=20(b+7)+10(b+7)+10

We simplify the equation to the form, which is simple to understand
10(b+28)+30(b+2)+40=20(b+7)+10(b+7)+10

Reorder the terms in parentheses
+(+10b+280)+30*(b+2)+40=20*(b+7)+10*(b+7)+10

Remove unnecessary parentheses
+10b+280+30+*(+b+2+)+40=+20+*(+b+7+)+10+*(+b+7+)+10

Reorder the terms in parentheses
+10b+280+(+30b+60)+40=20*(b+7)+10*(b+7)+10

Remove unnecessary parentheses
+10b+280+30b+60+40=+20+*(+b+7+)+10+*(+b+7+)+10

Reorder the terms in parentheses
+10b+280+30b+60+40=+(+20b+140)+10*(b+7)+10

Remove unnecessary parentheses
+10b+280+30b+60+40=+20b+140+10+*(+b+7+)+10

Reorder the terms in parentheses
+10b+280+30b+60+40=+20b+140+(+10b+70)+10

Remove unnecessary parentheses
+10b+280+30b+60+40=+20b+140+10b+70+10

We move all terms containing b to the left and all other terms to the right.
+10b+30b-20b-10b=+140+70+10-280-60-40

We simplify left and right side of the equation.
+10b=-160

We divide both sides of the equation by 10 to get b.
b=-16

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