10(b+3)=7(4+2b)

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Solution for 10(b+3)=7(4+2b) equation: 



10(b+3)=7(4+2b)

We move all terms to the left:

10(b+3)-(7(4+2b))=0

We add all the numbers together, and all the variables

10(b+3)-(7(2b+4))=0

We multiply parentheses

10b-(7(2b+4))+30=0



We calculate terms in parentheses: -(7(2b+4)), so:

7(2b+4)

We multiply parentheses

14b+28

Back to the equation:

-(14b+28)



We get rid of parentheses

10b-14b-28+30=0

We add all the numbers together, and all the variables

-4b+2=0

We move all terms containing b to the left, all other terms to the right

-4b=-2

b=-2/-4

b=1/2

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